added some usefull integrals
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alexander
2026-02-15 19:17:42 +01:00
parent 51554e8494
commit 6c273eef2d

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@@ -606,6 +606,13 @@
$tan(x) = (2t)/(1-t^2)$,
$cos(x) = (1-t^2) / (1 + t^2)$,
)
*Tricks aus der Schule*
$integral f(a x+b) d x = 1/a F(a x + b) +c \
integral (f'(x))/f(x) d x = ln abs(f(x)) \
integral f'(x) e^(f(x)) d x = e^(f(x)) +c \
$
])
#bgBlock(fill: colorIntegral, [
@@ -671,9 +678,21 @@
$integral 1/(x-a) d x = ln(x - a) + c\
integral 1/(x-a)^n d x = - 1/(n-1) 1/(x - a)^(n-1) + c quad "für" n >= 2 \
integral 1/((x - a)^2 + b^2) d x = 1/b arctan((x - a)/b) + c quad "für" n > 0\
integral (x - a)/((x-a)^a + b^2) d x = 1/2 ln((x-a)^2 + b^2) + c
integral (x - a)/((x-a)^a + b^2) d x = 1/2 ln((x-a)^2 + b^2) + c \
$
#grid(
columns: (1fr),
column-gutter: 2mm,
row-gutter: 4mm,
$integral 1/x d x = ln abs(x) +c$,
$integral 1/x^2 d x = - 1/x + c$,
$integral 1/(a + x) d x = ln abs(a + x) + c$,
$integral 1/(a + x)^2 d x = - 1/(a + x) + c$,
$integral 1/(a - x) d x = - ln abs(a - x) + c$,
$integral 1/(a - x)^2 d x = 1/(a - x) + c$
)
])